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  • Search Results for 'Sothatp3�p2=(q=p)(p2�p1)=(q=p)2p1;andmoregenerallypi 1�pi=(q P)ip1;0in:thuspi 1�p1=ixk=1(pk 1�pk)=ixk=1(q P)kp1;yieldingpi 1=p1 P1ixk=1(q'